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An angle originally measures -5pi/6. It then undergoes 2(5/6) clockwise rotations.

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1 Answer

First I need to verify that you are rotating clockwise 2 times by a measure of (5pi)/6.
 
A clockwise rotation would be subtracted from the original angle.
 
(-5pi)/6 - (5pi)/6 - (5pi)/6 = (-15pi)/6 = -2((3pi)/6
Each rotation around the axis is 2pi so -2((3pi)/6 = (-3pi)/6 = (-pi)/2