I believe your question looks like this? :
√(1)2√(2/3)

2
The root of 1 is 1:
12√(2/3)

2
This is the same as:
1 2√(2/3)
  
2 2
Let us deal with the root in the numerator first:
Because it is a root of the fraction, both the numerator and denominator can receive their own separate roots:
2√(2/3) = 2√2 ⁄ √3
so:
1 2√2 / √3
  
2 2
now we have division of fractions, so the problem becomes:
1 2√2 2
   * 
2 √3 1
then:
1 4√2
  
2 √3
we don't like to see roots in our denominator, so we multiply the numerator and denominator by √3, giving:
1 4√2√3
  
2 3
we can multiply our roots:
1 4√6
  
2 3
our LCD is 6, so:
3  8√6

6
Nov 6

Brian B.