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how do i solve this? 6/x+4/x+2=1

i dont know how to solve this. Help please!

Are we supposed to interpret this as:

A.  (6/x) + (4/x) +2 = 1

or

B. (6/x) + [4/(x+2)} = 1?

If A., then x = -10

If B, then x = -2*[(√7) - 2] or x = 2*[(√7) + 2]

It is supposed to be interpreted as B. 6 +  4 = 1
x   x+2
I still don't understand the process of getting to those numbers. I am supposed to
a. solve by completing the square         b. solve using the quadratic formula
OK, so the correct interpretation is B

(6/x) + [4/(x+2)} = 1

Complete the square method:

Multiply by x

6 =[4x/(x+2)] = x

Multiply by (x + 2)

(6)*(x + 2) +4x = (x)*(x + 2)

6x + 12 +4x = x2 +2x

6x + 12 + 4x = x2 = 2x

Therefore x2 - 8x = 12 or x2 - 8x - 12 = 0  [Let's call this Eq. (1)]

Take half the x coefficient, square it, and add to both sides

x2 - 8x + 16 = 12 + 16

(x - 4)2 + 16 = 28

(x - 4)2 = 28

from which x = -2*[(√7) - 2] or x = 2*[(√7) + 2]

x = [-b ±(b2 - 4ac)1/2]/2a

Going back to Eq. (1)

a = 1, b = -8, c = -12

x = {8 ± [64 - (4)(1)(-12)]1/2}/2(1) = {[8 ± √(112)]}/2}

From which

x = -2*[(√7) - 2] or x = 2*[(√7) + 2]

I hope this helps Mathalina!