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Solve algebraically 5x^2/4=2(x-1)

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2 Answers

5x2/4=2(x-1) or (5/4)x2-2(x-1) or (5/4)x2-2x+2=0
Multiply by 4 to get 5x2-8x+8=0 now use the quadratic formula
x=(8±√[64-4(5)(8)])/10
x=(8±√-96)/10 = (8±4i√6)/10 =(4±2i√6)/5
5x^2/4 = 2(x-1)

Multiply both sides by 4, yields:

5x^2 = 8(x-1)

Distribute the 8, yields:

5x^2 = 8x-8

draw all terms to left side, yields:

5x^2 + (-8)x + 8 = 0

a = 5; b = -8; c = 8

Apply Quadratic Formula:

[-b ± (b^2 - 4ac)^(1/2)] / (2a)