I need help solving this algebra question for my homework but in the shortest way possible

## can you solve 4(y-2)=3(y+5) in the shortest way ?

Tutors, please sign in to answer this question.

# 1 Answer

# 4(y-2)=3(y+5) step1: expand to get...

## 4y - 8 = 3y + 15 step2: combine like terms...

## 4y - 3y = 15 + 8 step3: calculate

## y= 23

## Detailed steps

4(y-2) = 3(y+5) Expand to get: 4y - 8 = 3y + 15

4y - 8 = 3y + 15 Subtract "3y" from each side: 4y - 3y - 8 = 3y - 3y + 15

4y - 3y - 8 = 3y -
3y + 15 You are left with: 4y - 3y - 8 = 15

4y - 3y - 8 = 15 Subtract "3y" from "4y" to get: y - 8 = 15

y - 8 = 15 Add "8" to each side: y - 8 + 8 = 15 + 8

y - 8 +
8 = 15 + 8 Your answer is: y = 15 + 8 or y = 23