lines a(1) and a(2 in two-dimensional space intersect at a point, forming an acute angle A. the slope of a(1) is square root of 5 , and cos A= 2/9. What is the slope of a(2)? There are two answers, both must be given to properly answer the question

tanθ

_{1}= √5, tanA = √(77)/2 (since cosA = 2/9, and A is an acute angle.)tanθ

_{2}= m, where m is the slope to be found.Since θ

_{2}-θ_{1 }= ±A,_{ }m = tan(θ

_{1}±A) = [tanθ_{1}±tanA]/[1-+tanθ_{1*}tanA]Plugging in tanθ

_{1}= √5, tanA = √(77)/2 gives you the exact final answers.Answer in decimal form: m = -.199 or m = -.752.