An airplane flew for 5 hours against a 20ph headwind. The return trip with the wind took 4 hours. Find the speed of the Plane in still air and explain how you arrived at your conclusion.
Find the speed of the airplane in still air.
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Let v = the speed in still air.
Balance by the distance,
(v-20)5 = (v+20)4
Solve for v,
v = 180 mph <==Answer
Hey Ryan -- in this story, the 40mph difference means an hour ->
Four 40's plus 20 wind = five 40's minus 20 wind = 180mph ... Regards, sir :)