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Solve algebraically x^3=x

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1 Answer

Solve for zero to get
 
x- x = 0
 
factor out an x to get
 
x(x2 - 1) = 0
 
Now factor what is in the parenthesis by using the difference of squares rule:
 
so
 
x(x - 1)(x +1) = 0
 
now solve for all three answers (separate the factors and set them ALL = 0)
 
x = 0  ,   x - 1 = 0  ,  x + 1 = 0
 
when you solve these three you get x = 0, x = 1, and x = -1
 
Bill Fanning
El Paso, TX