How to simplify the following x^8/2y*5y^2/x^3? Oct 17 | Gr from Cincinnati, OH | 3 Answers | 0 Votes Mark favorite Subscribe Comment
Since multiplying and dividng are equal in order...from left to right: [x^{8 }/ (2y)]*[(5y^{2})] / [x^{3}] = (x^{5} 5y)/2 Oct 17 | Alex V. Comment
I am interpreting this equation as: (x^{8}/2y)*(5y^{2})/(x^{3}) = [(5x^{5}y)/2] Oct 17 | William S. Comment
Hi Gr; x^{8}/2y*5y^{2}/x^{3} This can also be represented as... (x^{8}/2y)(5y^{2}/x^{3}) Let's consider x^{8}/x^{3 }. 8-3=5 This is now x^{5} (x^{5}/2y)(5y^{2}) Let's consider (1/y)(y^{2}). y is y^{1 }. Therefore 2-1=1 This is now y. (x^{5}/2)(5y) (5x^{5}y)/2 or (2.5)(x^{5}y) Oct 17 | Vivian L. Comment