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## how do you do two step equations

-1 over 3q-7=-3

Alexis, you have to use parentheses to avoid double reading!
(-1 over3)q-7=-3 or (-1/3)q - 7 = -3

1
-  ----  q  -  7  =  - 3
3
.                 + 7      + 7

1
-  ----  q  =  4
3
3                  3
×(- —)         ×( - —)
1                  1

q = - 12
Hi Alexis;
-1 over 3q-7=-3
This is...
-1/(3q-7)=-3
First, let's eliminate the complicated fractions.
We will multiply both sides by (3q-7)...
(3q-7)[-1/(3q-7)]=-3(3q-7)
Let's cancel where appropriate...
(3q-7)[-1/(3q-7)]=-3(3q-7)
-1=-3(3q-7)
Let's divide both sides by -3...
-1/-3=[-3(3q-7)]/-3
1/3=3q-7
Let's add 7 to both sides...
7+1/3=3q-7+7
7 1/3=3q
Because 7 1/3=22/3...
22/3=3q
Let's multiply both sides by 1/3 to achieve the isolation of q...
(22/3)(1/3)=3q(1/3)
22/9=q

Let's check our work...
The original equation was...
-1/(3q-7)=-3
-1/[3(22/9)-7]=-3
-1/[(22/3)-7]=-3
Because 7=21/3
-1/[(22/3)-(21/3)]=-3
-1/(1/3)=-3
Because dividing by 1/3 is equal to multiplying by 3...
-1(3)=-3
-3=-3
First - multiply both sides of the equation by the bottom portion of the fraction (3q-7) to eliminate the fraction.
Next - you are left with -1=-9q+21
Then - treat it like a normal equation. Subtract 21 from both sides to get -22=-9q
Finally - divide both sides by -9, and you find that q = 22/9. (or "22 over 9")

Good luck!