i have a homework problem from pre calculus and i dont understand how to solve it

## g(x)=x^3-1

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# 2 Answers

Are they asking you to graph it?

I'm reading the problem as g(x) = x

^{3 }- 1.Since it's Pre-Calc, I'm guessing they probably want you to graph it.

The parent function is f(x) = x

^{3 }.So 3 pts on f(x) are: (-1, -1), (0, 0), and (1, 1). Since the -1 will result in a downward shift of 1 unit,

the points on the graph of g(x) = x

^{3}- 1 would be (-1, -2), (0, -1), and (1, 0).You can graph it from there. It's concave down on the left side of the y axis and concave up on the right side of the y axis.

Hope this helps.

Jason

Hi Yozeline;

I am not exactly certain what this is...

g(x)=x

^{3-1}or

g(x)=(x

^{3})^{-1}Let's do both...

g(x)=x

^{3-1}=x^{2}This is because this is...

(x)(x)(x)

g(x)=(x

^{3})^{-1}This can also be expressed as...

g(x)=(x

^{3})/(x^{1})=(x^{3})/(x)This is because (x)(x)(x)/(x)

Henceforth...

x

^{2}It would be easier to say 3-1=2.

Is that the answer you are looking for?