Search 72,401 tutors FIND TUTORS
Search for tutors
Ask a question
0 0

(a5b0)3/(2ba3)=

Tutors, please sign in to answer this question.

2 Answers

Correct, otherwise it would be:
 
(a5b0)3
---------
(2ba3)
 
multiplication by 0 in the numerator would make it:
 
0
----
6ba
 
and 0 divided by any number (other than 0) is 0:
 
0
I'm going to assume the equation you wrote is this:
 
(a5•b0)3
---------   =  ?
(2b•a3)
 
The "cube" on the numerator's parentheses means 
 
a5•b0 • a5•b0 • a5•b0 
 
 
Since multiplying numbers means adding the exponents of the like terms, then
 
a(5+5+5)•b(0+0+0)  =  a15•b0
 
 
Thus you have
 
a15•b0
--------  = ?
2b•a3
 
 
The zero exponent means "1", therefore
 
a15•1
-------- = ?
2b•a3
 
 
Multiplication is commutative, so you can rearrange the denominator
 
a15•1
-------- = ?
a3•2b
 
 
And you can combine like terms into separate fractions, like this
 
a15     1
---- • ---- = ?
a3      2b
 
 
Dividing numbers means subtracting the exponents of the denominator from the exponents of the numerator, so
 
a(15-3) = a12
 
and
 
a12      1
---- • ---- = ?
  1      2b
 
Recombining results in
 
 a12 
------ = ?
  2b
 
 
So the answer is 
 
(a5•b0)3     a12 
--------- =  -----
(2b•a3)       2b
 
Of course, this is all assuming my interpretation of your problem is correct. Even if it's not, the principles shown here still hold.
 
Hope this helps!