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6a2+41a+63

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1 Answer

6a2+41a+63=0
 
63=7*9
 
(_a+7)(_a+9)
 
6=2*3
 
(3a+7)(2a+9)=0
3a+7=0; 2a+9=0
3a=-7; 2a=-9
a= -7/3; a= -9/2
 
CHECK:
FOIL
F: 3a*2a = 6a2
0: 3a*9 = 27a
I: 7*2a = 14a
L: 7*9 = 63
= 6a2+27a+14a+63
= 6a2+41a+63
 
REPLACE:
6(-7/3)2+41(-7/3)+63 = 0
6(-9/2)2+41(-9/2)+63 = 0