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logarithm 2x=2 3x-4

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logarithm 2x=2 3x-4  (variable x is introduced here)

2^s=2^(3x-4) and now variable S;
This problem seems a bit unclear:
If you mean to solve:
 
2X = 2(3X - 4), then this is straight forward(merely equate the exponents(x = 3x - 4; in which case x = 2)
 
please resend