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If a line crosses the y-axis at (0, 1) and has a slope of 4/5, what is the equation of the line?

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2 Answers

Hi Ari;
I do not know your background.  I am therefore going to assume you are unfamiliar with
y=mx+b
 
m=slope
b=y-intercept
 
It is a given fact that the line crosses the y-axis at (0,1)...
b=1
Therefore...
y=mx+1
 
It is a given fact that the slope of the line is 4/5...
m=4/5
Therefore...
y=((4/5)(x))+1
y = mx + b
 
m = 4/5, 
 
the point (0, 1) is the y-intercept, so b = 1
 
 
so,
 
y = (4/5)x + 1