HELP ME PLEASE :( .................

## If a line crosses the y-axis at (0, 1) and has a slope of 4/5, what is the equation of the line?

Tutors, please sign in to answer this question.

# 2 Answers

Hi Ari;

I do not know your background. I am therefore going to assume you are unfamiliar with

y=mx+b

m=slope

b=y-intercept

It is a given fact that the line crosses the y-axis at (0,1)...

b=1

Therefore...

y=mx+1

It is a given fact that the slope of the line is 4/5...

m=4/5

Therefore...

y=((4/5)(x))+1

y = mx + b

m = 4/5,

the point (0, 1) is the y-intercept, so b = 1

so,

**y = (4/5)x + 1**