HELP ME PLEASE :( .................
If a line crosses the y-axis at (0, 1) and has a slope of 4/5, what is the equation of the line?
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I do not know your background. I am therefore going to assume you are unfamiliar with
It is a given fact that the line crosses the y-axis at (0,1)...
It is a given fact that the slope of the line is 4/5...
y = mx + b
m = 4/5,
the point (0, 1) is the y-intercept, so b = 1
y = (4/5)x + 1