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Algebra word problem for 5th grade

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3 Answers

Let F be the cost of one lady finger
Let C be the cost of on cookie.
 
so,
 
F + 6C = 3.05          eq. 1
2F + 4C  = 2.50       eq. 2
 
use eq. 1 to solve for F:
 
F = 3.05 - 6C          eq. 3
 
subsitute eq. 3 to eq. 2
 
2(3.05 - 6C) + 4C = 2.50
 
6.10 - 12C + 4C = 2.50
 
6.10 - 8C = 2.50
 
6.10 - 2.50 = 8C
 
3.60 = 8C
 
so C = $.45
 
so, each cookie costs 45ยข
 
 
 
 
Hey Darlene!
"cut in half" idea: one LF and two C costs $1.25 ... 4 less cookies saves $1.80 
"halving tool" again => 4C is 1.80 ... 2C is 0.90 ... one cookie is 45 cents ... Regards :)
First, set up an algebraic equation:
lady finger = x
cookie = y
 
x+6y=3.05
2x+4y=2.50
 
Then, solve for one variable...
x=3.05-6y
 
Then, plug in your new equation into the other equation...
 
2(3.05-6y)+4y=2.50
 
6.1-12y+4y=2.5
 
3.6=8y
y= 0.45
 
Since Y is the price of a cookie, the price of a cookie is 45 cents/$0.45.
 

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