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I need to find the equation of the line parallel to y=3 and it goes through points (2,-1) and put it in slope intercept form

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2 Answers

Are you sure you have understood the problem correctly? The line y=3 is a horizontal line, and a horizontal line has a slope of zero. The only lines parallel to a horizontal line are other horizontal lines. Therefore, there is no slope. The slope is the coefficient of x in the slope-intercept form: y = mx + b. m stands for the slope, and b is the y-intercept.
Jenifer,
 
slope  = (y2 - y1) / (x2 -x1)
 
so
y - y1 = m (x -x1)
 
the point (2 , - 1)
 
Equation of a line  is  y =mx + c
 
where m is the slope
 
y =3 has zero slope so m = 0 and parrle line to this must have m = 0 as well
 
Back to the point of (2, -1)  using y -y1 = m(x -x1)
 
We will have
 
y - (-1) = m(x -2)
 
y + 1 = 0 - 0
 
y = -1
 
And you have it...
 
 
Remember that  y = 2x + 3 and y = 2x - 6 have the same slope of  m =2 (i.e. parallel)
 
Also y = 1/4x + 22/3 and y = 1/4x  + 100 also have the same  slope of  m = 1/4
 
And as well y = 8 and y = 1000 have the same slope of m = 0
 
Let me know if you have any more questions or need more help.