I need to find the equation of the line parallel to y=3 and it goes through points (2,-1) and put it in slope intercept form

## I need to find the equation of the line parallel to y=3 and it goes through points (2,-1) and put it in slope intercept form

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# 2 Answers

Are you sure you have understood the problem correctly? The line y=3 is a horizontal line, and a horizontal line has a slope of zero. The only lines parallel to a horizontal line are other horizontal lines. Therefore, there is no slope. The slope is the
coefficient of x in the slope-intercept form: y = mx + b. m stands for the slope, and b is the y-intercept.

Jenifer,

slope = (y2 - y1) / (x2 -x1)

so

y - y1 = m (x -x1)

the point (2 , - 1)

Equation of a line is y =mx + c

where m is the slope

y =3 has zero slope so m = 0 and parrle line to this must have m = 0 as well

Back to the point of (2, -1) using y -y1 = m(x -x1)

We will have

y - (-1) = m(x -2)

y + 1 = 0 - 0

y = -1

And you have it...

Remember that y = 2x + 3 and y = 2x - 6 have the same slope of m =2 (i.e. parallel)

Also y = 1/4x + 22/3 and y = 1/4x + 100 also have the same slope of m = 1/4

And as well y = 8 and y = 1000 have the same slope of m = 0

Let me know if you have any more questions or need more help.