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The Maximum Weight

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2 Answers

Maximum weight =k W*H^2/L, where k is a constant.
10 = k(1/3)(1/4)^2/17 = k/816......(1)
x = k(3/4)(1/3)^2/13 = k/156 ......(2)
(2)/(1): x/10 = 816/156 = 68/13
x = 680/13 = 52.31 tons <==Answer
 
Hi again, Theresa -- since the 2nd beam is fatter and shorter, we can expect GREATER load support ... width bigger 9/4x ... ht bigger 4/3x ... h^2 bigger 16/9x ... L smaller 13/17 => bigger load by 17/13 ... expect bigger load of 9/4(16/9)17/13 ...  4(17/13) ... 68/13 ...
5 1/4x ==> 52.5 tons :)

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