Find the slope -intercept form of the equation of a line that passes through the given points. (6,-9),(-2,3) I solved it and this is what I got -12/8=1.5 If I am wrong let me know and tell me the steps and solved it for me 9/28/2013 | Ma from Los Angeles, CA | 2 Answers | 0 Votes Mark favorite Subscribe Comment
First thing you have to do is get the slope (y2-y1)/(x2-x1) = slope lets make (6,-9) point 1, and (-2,3) point 2 you dont really need to do this part but it helps so x1 = 6 y1 = -9 x2 = -2 y2 =3 (3 - -9)/(-2 - 6) = 12/-8 or -3/2 now the Point-Slope Equation of a Line is y - y1 = m(x - x1) so lets plug in Y - -9 = (-3/2)(X - 6) or Y +9 = (-3/2)(X-6) 9/29/2013 | Justin L. Comment
what you have found is correct but i think you accidentally lost your sign -12/8 is correct which will simplify as -3/2 or -1.5 . Next you will have to write out the slope intercept form equation Y = MX + b Now plug in the order pair (either one) into X and Y. I picked (-2,3) 3 = (-3/2)*(-2) + b 3 = 3 + b now solve for b by subtracting 3 on both side of the equal side 0 = b Therefore Equation will be: Y= -3X/2 + 0 Or Y=-3X/2 I hope this helps! 9/28/2013 | Priti S. Comment