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write the complex number in standard form?

write the complex number in standard form: (3-2i)^2(3+2i)
                                                              ---------------------
                                                                       (5-i)
 
Step by step would be great! I have a test tomorrow that I have to take a day early and I need to learn this stuff!
thank you!
-Addie
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1 Answer

 
(3-2i)^2(3+2i) = (3-2i)(9+4) = 13(3-2i), since (3-2i)(3+2i) = 9+4
1/(5-i) = (5+i)/26
So,
 
(3-2i)^2(3+2i)/(5-i)
= 13(3-2i)(5+i)/26
= (1/2)(15+2 +3i-10i)
= (17/2) - (7/2)i <==Answer

Comments

the problem is actually (3-2i) to the second power.
(3-2i)^2 (3+2i) all over (5-i)
 
 
(3-2i)^2 (3+2i)
------------------
       (5-i)

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