its a algebra word problem

## have nuts that cost $9.00 per pound and 50 pounds of nuts that cost $5.00 per pound how many pounds do i need to get a mixture that cost $6.50 per pound

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# 2 Answers

Here again choose a variable for the unknown, what problem is asking you to find out.

X - amount of $9.00/ lb need to be mixed with $5.00/ lb

X ( 9.00) + 5( 50) = ( X + 50) (6.50) to mixing means adding up the weights .

9X + 250 = X ( 6.50) + 325

9X - 6.50 X = 325 - 250

2.50 X = 75

X = 75/ 2.50 = 30 lb

You are given the amount of the cheaper nut: 50 lbs.

You need to know the amount of the more expensive nut; let that be x.

The total weight of the final mixture is 50+x.

So we have x pounds times $9 plus 50 pounds times $5 equals $6.50 times the sum of x and 50.

9x + 5*50 = 6.5*(x+50)

9x + 250 = 6.5x + 325

9x = 6.5x +75

2.5x=75

x = 30

Adding 30 lbs of the more expensive nut will create 80 lbs of a mixture that costs $6.50 per pound.