what is the answer to this ?
Let F(t) represent the average rate of change in the growth of bacteria with respect to time (t) in hours.
Let ƒ(t) represent the amount of bacteria in the sample at time t.
At time t1= 1 hour, the amount of bacteria in the sample is ƒ(t1) = ƒ(1) = 250
At time t2= 3 hours, the amount of bacteria in the sample if ƒ(t2) = ƒ(3) = 1000
The average rate of change is represented by the following formula:
F(t) = [ƒ(t2) - ƒ(t1)] / (t2 - t1)
= [ƒ(3) - ƒ(1)] / (3-1)
= (1000 - 250) / (2)
= (750) / (2)
F(t) = 375
Thus, the average rate of the growth of the bacteria in the sample is 375. That is, the amount of bacteria in the sample is increasing/growing at a rate of 375 bacteria per hour.