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a camera cost 91.98 and the case is equal 6times the cost of the camera how much is the case?

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4 Answers

Jamark, was the problem originally written something like this:
 
A camera with case costs 91.98. If the cost of the case itself is 6x the cost of the camera, how much does the case cost?
 
Solution: [let x = cost of the camera]
 
1)  The cost of the camera (x) plus the cost of the case (6x) = 91.98
2)  x + 6x = 91.98
3)        7x = 91.98
4)  Divide 91.98 by 7 to get the value of x
5)          x = 13.14
6)  The cost of the camera (x) is 13.14. The cost of the case (6x) is therefore 6 * 13.14 = 78.84
 
Check your work!
7)  Replace 13.14 for 'x' in the equation [step 2) above]
8)  (13.14) + (6*13.14) = 91.98
9)  13.14 + 78.84 = 91.98
10)   91.98 DOES = 91.98 
 
The cost of the camera = 13.14
The cost of the case = 78.84
 
*After you solve the equation, always reread the original question to ensure you answer what the problem is asking!
Multiply 6 times 91.98
6(91.98) = $551.88

Comments

The currency was not provided in the question; the cost of the case is 551.88. Some teachers may mark this as incorrect if you provide the wrong currency or unit of measurement.
 Very simply what is 6 times 91.98
 
    91.98 * 6 = 551.8 8
   
     Math is about relationship between 2 objects regardless of their nature.

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