I assume you are asking for the solution of the system. Then, the solution is the (x, y) pair that is a solution to BOTH equations. Hence, the y value is the same at that point. Let's solve each equation for y:
y = 2x  1 and y = 3x + 1
Since the y values are the same in each case, by substitution
2x  1 = 3x + 1
Then, subtracting 2x and 1 from each side, we have
2 = x.
Substituting this value of x, we get y = 2(2)  1 and y = 3(2) + 1. This yields y = 5 in each case.
Let's check.
2(2)  1 = 4  1 = 5 and 3(2) + 1 = 6 + 1 = 5
9/17/2013

Mark R.
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