i dont know how to solve these

## Find the x-int(if possible), y-int and axis of symmetry of the quadratic function. a) y=f(x)=x^2-6x+9 b)y=g(x)=x^2-x-2 c) y=h(x)=2x^2+x-6 d) y=j(x)=9-x^2

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# 1 Answer

Hello again, M -- Yint happens when x=0 ... a) Yint = 9 ... you may try the rest

Xint is when y=0 ... a) x^2 -6x +9 =0 factors (x-3)(x-3) => Xint=3 ... you may factor rest

axis of symm for y= ax^2 +bx +c is x= -b/(2a) ... a) axis is x= -(-6)/(2*1) ==> x=3 ... try rest :)