What is the distance from the point (1,-3,8) to the x-axis? This is a calculus 3 question.

## What is the distance from the point (1,-3,8) to the x-axis?

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# 2 Answers

Drop perpendicular to the x-axis, it intersects x-axis at the point (1,0,0). The vector from the point (1,0,0) to the point (1,-3, 8) is perpendicular to the x-axis and its length gives you the distance from the point (1,-3,8) to the x-axis. The coordinates
of a vector are (0,-3,8). Its length is √(0

^{2}+(-3)^{2}+8^{2})=√73. This is your answer.Distance between 2 points P1 to P2 in XYZ or 3-space is |P1P2| =

square root of [(X

_{2}- X_{1})^{2}+ (Y_{2}-Y_{1})^{2}+ (Z_{2}-Z_{1})^{2}]