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Find the equation of a line with a slope of 3/4 that goes through the point (8, 2).

You may want to use point slope to write the equation of the line, given this information that would be the easiest to use.  The form is Y-Y1=m(x-x1)

m = slope
x1 = the x coordinate
y1 = the y coordinate

therefore, replacing that information into the equation would give you

y-2=(3/4)(x-8)
use y = mx + b equation where m is the slope and b is the y-intercept. We are given m which is 3/4. We are also given x and y which are 8 and 2, respectively.

so, we plug in these values to solve for b:

2 = (3/4)8 + b

2 = 6 + b

so, b = -4

therefore, y = (3/4)x -4

You want to use the slope-intercept equation for a line. This form is Y =M X + B, or, Y-value = Slope * X-value + Y-Intercept.

What we know is an X value, a Y value and a Slope.
X = 8, Y = 2, M = 3/4

By substitution we can solve for B

2 = 3/4 * 8 + B

or
B = -4

Thus equation for the line would be: Y = (3/4) * X - 4

The check (should get 2 for Y if plug in 8 for X):
Y = 3/4 * (8) -4 = 6 - 4 = 2