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[3*32+13*(-2)]+7[8-(4-9)]

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3 Answers

The key in this problem is to apply the order of operations correctly.
 
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AS
 
[3*32+13*(-2)] + 7[8-(4-9)]
 
Parentheses:  perform any operations within parentheses first
 
(4-9) = -5  -->   [3*32+13*(-2)] + 7[8-(-5)]
 
[8-(-5)] = 13  -->  [3*32+13*(-2)] + 7*13 = 3*32 + 13*(-2) + 7*13
 
Exponents: none in this problem
 
Multiplication and Division left to right:
 
3*32 = 96  --> 96 + 13*(-2) + 7*13
 
13*(-2) = -26  -->  96 + (-26) + 7*13
 
7*13 = 91  --> 96 + (-26) + 91
 
Addition and Subtraction left to right:
 
96 + (-26) = 70  -->  70 + 91 =161