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4y^ - 8y^4 / 2y^3

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2 Answers

to make this easier, lets rewrite the equation:

4/2(y^(-8y^4))/(y^3) = 2(y^(-8y^4))/(y^3)

when you divide by powers with the same base, (in this example, base "y") you subtract.

so,

2(y^(-8y^4))/(y^3) = 2(y^((-8y^4)-3))

Hope this helps! :)

Comments

I apologize. It seems I misinterpreted your question =X The above answer is for y^(-8y^4)/y^3

Comment

am • an = am + n  
am ÷ an = am - n  
              1
a - m  =  ——  
              am 
~~~~~~~~~~~ 
  4 y -8 y4           4
 —————  =  ——   y - 8 + 4 - 3   
     2 y3             2 
                   2
= 2y - 7  = 
                   y7