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identify the line of symmetry of then parabola defined by y=-2(x+w)^2+6

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Hi, Maira.

The vertex form of a parabola is written y = a(x-h)2 + k  where h and k are the coordinates of the vertex of the parabola.

The x-coordinate of the vertex, or h, also represents the axis of symmetry.

So in your problem y=-2(x+w)^2+6, the axis of symmetry would be x = -w  (Note that in the general form it is x - h inside the parentheses, so the sign changes.)

Hope this helps!

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