Search 75,906 tutors
0 0

## identify the value of the discriminant for the equation 6x^(2)=2x-1

a. -20

b. 28

c. 24

d. -22

Hi, Maira.

The discriminant is the part of the quadratic formula that is under the radical sign, that is, b2-4ac. You can use it to determine how many real solutions the equation has.

First, bring all the terms to one side of the equation:

6x2 - 2x + 1 = 0

a = 6
b = -2
c = 1

b2 - 4ac  =  (-2)2 - 4(6)(1) = 4 - 24 = -20

The discriminant is -20. (This also tells you that there are no real solutions to this equation.)

Hope this helps!

To put the equation, 6x^2 = 2x - 1 into the standard quadratic equation form, that is: ax^2 + bx + c = 0, subtract (2x - 1) from both sides to yield 6x^2 - 2x + 1. Then, a = 6, b = -2, and c = 1. The discriminant indicates the nature of the equation's roots (complex or real) and is defined as b^2 - 4ac. The discriminant becomes (-2)^2 - 4*6*1 = 4 - 24 = -20. Therefore, the answer is a. Note that the negative value indicates that the roots to this equation are complex.

6x2 = 2x – 1
6x2 – 2x + 1 = 0
a = 6, b = - 2, c = 1
D = b2 – 4ac
D = (- 2)2 – 4 • 6 • 1 = 4 – 24 = - 20