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## word math problem

1) An investor a total of \$1,600 in two mutual funds. One fund earned a 6% profit while the other earned 3% profit. If the investorâ€™s total was \$78, how much was invested in each mutual fund?

The amount in the mutual fund that earned 6% was______

The amount in the mutual fund earned 3% was_________

lets look at the amount earned.

WHAT DO I KNOW?

I know that 6% of \$x + 3% of whats left (\$1600-x) = \$78

Now REMEMBER.... PERCENTS ARE ALWAYS HUNDRETHS!

So  6/100 times x + 3/100 times (1600-x) must = \$78

now we have  (6/100) * x) + (3/100) *1600) - (3/100) * x =  78

then 6x/100 +4800/100 - (3x/100) = 78  or  6x/100 - 3x/100 +4800/100 = 78

therefore 3x/100 + 48 = 78 or 3x/100 = 30 or 3000 = 3x and therefore x = 1000.

The amount in the mutual fund that earned 6% was 6% of \$1000 = \$60

The amount in the mutual fund earned 3% was 3% of \$600 = \$18

totaling \$78.

so \$1000 earned 6% and \$600 earned 3%

There are other ways to do this, but this is pretty straight forward.