Solve the following equation fory: 2 + √4y – 3 = 11
A. y = 18
B. y = 3
C. y = 36
D. y = 6
Solve the following equation fory: 2 + √4y – 3 = 11
A. y = 18
B. y = 3
C. y = 36
D. y = 6
It's hard to tell if the radical extends over the 4 & y, or just the 4. The answer will vary depending which is true.
2 + sqrt(4)y -3 = 11 * get all the numbers on one side, subtract 2 and +3 to both sides
sqrt(4)y = 12 * divide by sqrt(4) on both sides
y = 12/sqrt(4) * square both sides
y^2 = (12^2)/(sqrt(4)^2)
y^2 = 144/4
y^2 = 36 * take the sqrt of both sides
y = +6 or -6
OR
2 + sqrt(4y) -3 = 11 * get all the numbers on one side, subtract 2 and +3 to both sides
sqrt(4y) = 12 * square both sides
4y = 12^2
4y = 144 * divide both sides by 4
y = 36
Y:2 + √4Y-3 = 11
+3 +3
y: 2+ √4Y = 14
-2 -2
Y: √4Y = 12
(√4Y)^{2} 12^{2}
Y: 4Y = 144
⁄4 /4
Y: 36