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Solve the following equation for y: 2 + v4y – 3 = 11

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2 Answers

It's hard to tell if the radical extends over the 4 & y, or just the 4.  The answer will vary depending which is true.

 

2 + sqrt(4)y -3 = 11   * get all the numbers on one side, subtract 2 and +3 to both sides

sqrt(4)y = 12             * divide by sqrt(4) on both sides

y = 12/sqrt(4)            * square both sides

y^2 = (12^2)/(sqrt(4)^2)

y^2 = 144/4          

y^2 = 36                   * take the sqrt of both sides

y = +6 or -6

 

OR

 

2 + sqrt(4y) -3 = 11 * get all the numbers on one side, subtract 2 and +3 to both sides

sqrt(4y) = 12           * square both sides

4y = 12^2

4y = 144                  * divide both sides by 4

y = 36

 

 

Y:2 + √4Y-3   =   11

              +3         +3

y: 2+ √4Y      =    14

    -2                    -2

Y: √4Y    =    12

    (√4Y)2       122

Y:    4Y     =    144

      ⁄4             /4

Y:   36