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How many excess electrons does the dome of a van de Graff generator posses? What is the increase in mass because of their presence?

Physics/Chemistry:

The dome of a van de Graff generator carries a negative charge of 8.0 x 10-7C.

How many excess electrons does it posses? What is the increase in mass because of their presence?

I'm just asking for a step-by-step solution or an explanation.

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1 Answer

1) Use dimensional analysis:

8.0 x 10-7C (1 e/ 1.6*10-19 C) = 5 * 1012 excess electrons

 

2) Use dimensional analysis:

5 * 1012 e (9.11 * 10-31 kg / e) = 4.555 * 10-18 kg

 

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