This is a exponents problem that i need help with.
Your fourth term is 192, no? In that case the formula is 3*4^(n-1), where n is the term number.
This is a exponents problem that i need help with.
Your fourth term is 192, no? In that case the formula is 3*4^(n-1), where n is the term number.
r = 12/3 = 4, the common ratio
So, the nth term t(n) = t(0) r^(n-1) = 3 (4)^(n-1) <==Answer
This is called a geometric sequence because there is a constant multiplier of 4. If you use b(m)^n where b is the term that would come BEFORE the 1st term, and m is the constant MULTIPLIER, you get (3/4)4^n.