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how do you solve linesr equqtions?

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3 Answers

Does this problem come with a second equation? If there are two variables, you need at least two equations to be able to find the value of each variable. 

Assuming your two equations are 2x+3y=12 and 6x+4y=12 then you would do the following to solve for x and y:

2x+3y=12 & 6x+4y=12

2x+3y=12=6x+4y

2x+3y=6x+4y

subtract 2x from both sides 2x+3y -2x = 6x+4y -2x

3y=4x+4y

subtract 4y from each side 3y -4y= 4x+4y -4y

-y = 4x

multiply each side by negative one (-1)*-y = (-1)*4x

y=-4x

input the y value into the original equation 2x+3(-4x)=12

2x-12x=12

-10x=12

x=-12/10=-6/5=-1.2

now input your x value into the original equation to solve for y

2(-6/5)+3y=12

-(12/5)+3y=12

3y=12+(12/5)=((12*5)/5)+(12/5)=(60/5)+(12/5)=72/5

y=(72/5)/3=72/(3*5)=(72/3)/5=24/5=4.8

x= -6/5        y= 24/5

if you put both the x and y values into the equation 2x+3y or 6x+4y they will both equal 12

 

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