I an trying to find the domain and range of f(x) square root x-3
Domain of the function ƒ(x) is the set of values of "x" or "input" for which the function is defined.
Range of the function ƒ(x) = y is the values of "y" or output"
In set of real numbers √a is the real number if a ≥ 0
Domain (possible value of "x"):
ƒ(x) = √(x - 3) is defined in set of real numbers if (x - 3) ≥ 0
x - 3 ≥ 0
x ≥ 3 or [3, +∞)
Range (possible value of "y"):
The minimum value of given function: ƒ(3) = 0
y = ƒ(x) ≥ 0 or [0, +∞)
the domain is x≥3 and the range is y≥0
x-3≥0 = x≥3 (by adding three to both sides) = Domain
For range, y can be any number greater than 0, because when y=0 x=3 = Range
You can check this also by entering the equation in a calculator