Solve the systems of linear equations by using the method of substitution. If the system is consistent, inconsistent, or dependent, say so in your answer. 5x+y=1 3x+y=3

5x + y = 1 ..... (1) 3x + y = 3 ..... (2)

Let's solve (1) for "y":

y = 1 - 5x , and substitute "y" in (2) by (1 - 5x)

3x + (1 - 5x) = 3

3x + 1 - 5x = 3 ---> -2x = 2 ---> **x = -1**

Now, we have to replace "x" by its value in one of two equations in order to find value of "y"

5(-1) + y = 1 ---> y = 5 + 1 --->** y = 6**

The answer is pair of numbers * (-1, 6)* and system is

*.*

**consistent and independent**