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what does y equal in the equation y+3/y=9

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if this is (y+3)/y = 9: 9 can also be written as 9/1 therefore if you cross multiple across the parenthesis,        9y = y+3; 8y = 3; y = 3/8

if this is y + 3/y = 9; the equation can be multiplied by y on both sides and set equal to 0 to get y^2 - 9y + 3 = 0; using the quadratic equation, y= (-b[+/-]sqrt(b^2 - 4ac))/ 2a where ay^2 + by + c = 0 so a=1 b=-9 c=3, y = (9 + sqrt(69))/2 & (9 - sqrt(69))/2

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