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Find the area of the parallelogram?

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1 Answer

This one is actually a classic problem for cross products.

<1, 0, -1> × <-2, 2, 0>

      |  i     j    k  |

=    |  1    0   -1 |

      | -2    2    0 |

= <0*0 - (-1)*2, (-1)*(-2) - 1*0, 1*2 - 0*(-2)>

= <2, 2, 2>

Area = ||<2,2,2>|| = √(22 + 22 + 22) = 2√3.