I keeping getting it wrong and don't know what else to do.
I need help for two questions to solve 4^3x=8 & 4^2x=7 by graphing?
You have to make a list of x and y values.
1) For your first equation (y = 43x) you will have
x 0 1/3 1/2 1
y 1 4 8 64
Since 43x = 8 your anwerr is x = 1/2. For the right side y = 8 - horizontal line intersecting y=43x
at x = 1/2.
2) The same way, for the second equation you can make a chart
x 0 1/4 1/2 1
y 1 2 4 16
Since the right side is y =7, function y = 42x will intersect y = 7 line at 1/2 < x <1. If you solve it analytivally (by taking logarithms) you will find that in this case x = 0.702 (x = ln7/2ln4). Use the numbers shown to sketch the graph to make sure that x = 0.702. Good luck!