Please solve it step by step

## (a2+b2)2 please solve it

# 2 Answers

(a^{2} + b^{2})^{2}

Notice that the binomial is being squared, so it expands to the following expression:

(a^{2} + b^{2})^{2} = (a^{2} + b^{2})(a^{2} + b^{2})

By the distributive property, while applying the product of exponents with like bases and combining like terms, we arrive at the following:

(a^{2} + b^{2})(a^{2} + b^{2}) = (a^{2} · a^{2}) + (a^{2} · b^{2}) + (b^{2} · a^{2}) +
(b^{2} · b^{2})

= (a^{2+2}) + (a^{2}b^{2}) + (a^{2}b^{2}) + (b^{2+2})

= a^{4} + 2a^{2}b^{2} + b^{4}

(a^{2} + b^{2})^{2} is the same as saying (a^{2} + b^{2})(a^{2} + b^{2})

When we FOIL the two binomials, we get:

a^{4} + a^{2}b^{2} + a^{2}b^{2} + b^{4}

After simplifying,we get the solution:

a^{4} + 2a^{2}b^{2} + b^{4}