I got intercept = (3, 0); y-intercept = (0, -4). Am I right?
I am doing homework and this is the equation: y= -x -4 along with graph to chart it on. We are working on integer linear equations and graphing on charts. If you could help, it would clear some things...
what do i do with the 1?
7 x (-6) x 5 x(-4) x 3 x (-2 x 1 x 0 =
cannot understand these problems; find the domain of the function and express the answer in interval notation.
then explain in words or show work. a) f(x) = 4x2 - 7x +3 b) g(x) = 10 over x+7 c) f(x) = √4x - 16 d) g(x) = 2x over x-3 e) f(x) = 3x -9
Word Problems (system of equations)
8x+6=4x+26 step by step how to would be nice
6sqrtxy-32y^4 +56y^2 =3y(6y^3+5y) solve for x
An endpoint and the midpoint of a line segment are respectively (-3,-1) and (-1,1). Find the other endpoint.
how towrite a polynomial equation to model a 4 th degree polynomial with functions values of 0,,5 10, and 15
suppose that you are told that a good model for a situation is a 4th degree polynomial. You know that the function must have values of 0 for the input of 0,5,10,and 15.Write a polynomial equation...
4x^2-4y^2 cant solve this problem
I can't figure these out and any help would be appreciated! Thank you! 1. 9(√6-2) 2. (6√2+8√3)(√2+9√3) 3. (√6+x)2 4. (3√4-6)(3√2+6) 5. (√x-3+5)2 6. 7y√20y+9√2...
Problem 1) √4 - x = -2 x -2 x -2 Problem 2) √x + 2 - x = 0 Was confused on the answers; please re-advise
having problems solving problems step by step (equations algebraically) and really need some help on this issue
t and 2 3rds = 4 5 sqrt x+ 1 = 3 2/3 =2 - 5x-3 over x-1
I've been having trouble with Absolute Values and my teacher has been speeding ahead, and I'm not understanding any of it! Help meee~ Please.
I need to find the value of 'x' in this quadratic equation
How do I get the answer (x+4) (x-1), from x^2+4x-x-4? Please explain step by step. sharon
im trying to solve this equation x over 3 plus 1= x over 6,,,it seems so simple but puzzling if you don't know where to start
help me solve x2+3x-10=0