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# find the distance between the points (-2,5) and (12,-1)

Dear Louis,

You can figure out the precise distance between these two points by using what you know about right triangles:  that the sum of the squares of the legs equals the square of the hypotenuse.

Here's how.  First, plot both of these points (-2, 5) and (12, -1) on a piece of graph paper.  Then what I want you to do is draw two lines:  the first is a horizontal line going from (-2,5) to (12, 5).  Then, turning the pencil in a different direction, draw a vertical line that goes from (12, 5) to (12, -1).

Voila.  You have a right triangle and you will notice the length of the hypotenuse of this triangle is precisely equal to the length between these two points.  If you count the tick-marks, you'll notice the legs of this right triangle have lengths 14 and 6.  14 squared plus 6 squared is equal to 232.  The answer is, therefore, that the length is the SQUARE ROOT OF 232 or about 15.23.

The quick method is to think the DIFFERENCE in X is one leg of the triangle and the DIFFERENCE in Y is the other leg of your triangle.   The difference between (-2) and 12 is 14.  The difference between 5 and -1 is 6.  Etc.

Mr. Gets Results

d = √((x1 - x2)2 + (y1 - y2)2)
( -2 , 5 )   ( 12 , -1 )
↑    ↑         ↑     ↑
x1    y1        x2    y2

d = √((-2 - 12)2 + (5 - (-1))2) = √((-14)2 + 62) = √(196 + 36) = √232 = 2√58 ≈ 15.23

The distance between two  points (x1,y1) and (X2,Y2) can be found by using the formula d =  √ (x2-X1)²+(Y2-y1)²

you can find the distance for the points (-2,5) and (12,-1) using the above formula

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