Search 74,088 tutors

# How to mutiply (14x-28y)/[-7(x-2y)]

There are a few ways to do this.

• (14x-28y)/[-7(x-2y)]
• [14(x-2y)/[-7(x-2y)]  Factor 14 out of each term of the numerator
• 14/-7                      Cancel (x-2y) out of the numerator and denominator
• 14/-7  = -2

The other way is more complicated, but will yield the same results

1. (14x-28y)/[-7(x-2y)]
2. (14x-28y)/(-7x+14y)   Distribute the -7 across the two terms in the denominator. Then we'll divide.
3.                                 Think long division, how many times does -7x go into 14x  .... -2 times
4. -2(-7x+14y) = 14x-28y Then well subtract from the numerator to see what the remainder is.
5. (14x-28y)-(14x-28y) = ?
6. (14x-28y) + -1(14x-28y) = ?  Rewrite for clarity
7. 14x - 28y -14x + 28y = ?  Distribute the -1.
8. 14x - 14x + 28y - 28y = 0  We can see that this will equal zero so there is no remainder
9. So our final answer is -2 with no remainder or just -2 from step 3

Factor out 14 in the numerator,

(14x-28y)/[-7(x-2y)]

= [14(x-2y)/[-7(x-2y)]

= -14/2, after canceling x-2y.

= -7