When i multiply, i get the answer wrong.
How to mutiply (14x-28y)/[-7(x-2y)]
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There are a few ways to do this.
- [14(x-2y)/[-7(x-2y)] Factor 14 out of each term of the numerator
- 14/-7 Cancel (x-2y) out of the numerator and denominator
- 14/-7 = -2
The other way is more complicated, but will yield the same results
- (14x-28y)/(-7x+14y) Distribute the -7 across the two terms in the denominator. Then we'll divide.
- Think long division, how many times does -7x go into 14x .... -2 times
- -2(-7x+14y) = 14x-28y Then well subtract from the numerator to see what the remainder is.
- (14x-28y)-(14x-28y) = ?
- (14x-28y) + -1(14x-28y) = ? Rewrite for clarity
- 14x - 28y -14x + 28y = ? Distribute the -1.
- 14x - 14x + 28y - 28y = 0 We can see that this will equal zero so there is no remainder
- So our final answer is -2 with no remainder or just -2 from step 3
Factor out 14 in the numerator,
= -14/2, after canceling x-2y.