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# y = 2x2 + 12x +10

To solve this equation you must have more information.  Because there is both x and y variables there will be a range of answers for both.  If it is a quadratic equation the y has a 0 value.  Then you can begin the process of factoring and finding the solutions.

0=2x^2+12x+10

0=2(x^2+6x+5)

The two is eliminated.

0=(x+5)(x+1)

x+5=0

x=-5

x+1=0

x=-1

x=-1,-5

Problem: y=2x2+12x+10

Step 1: Factor out common number that is shared by each of the terms. Basically in this step we are trying to get rid of the coefficient in front of the x2 so we can simplify the quadratic eqn and in turn factor easily.

y=2(x2+6x+5)

Step 2: factor the polynomial inside the parenthesis

x2+6x+5 becomes or is equal to (x+5)(x+1)

Hence: y=2((x+5)(x+1))

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If this problem asks what x would be if y=0, then the following step is your solution. Otherwise, the simplified form is a factored solution.

Step 3: y=0

0=2((x+5)(x+1))

0=(x+5)(x+1) --> In multiplication, if either or both of the numbers were to be 0, the

product is 0. (Eg. 2*0=0....or....0*0=0)

So have (x+5)=0 and (x+1)=0

Then x=-5    and x=-1

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