This a question on my algebra hw I need help
What is the x-coordinate of the solution to the system x+y=5X-2y=-1
3 Answers
Hello, here's the solution to your problem:
x + y = -1
5x - 2y = -1
1) Solve for x for the first equation: y = -x -1
2) Substitute that value for y into the second equation: 5x - 2(-x-1) = -1
3) Solve for x: 7x = -3 => x = -3/7
x+y = 5X-2y = -1 (This is really saying that these three things all are equal.)
- x + y = -1
- 5x - 2y = -1
- x + y = 5x -2y
There are a couple of different ways we can solve this.
Substitution:
- x + y = -1
- y = -x - 1 (subtract x from both sides)
- 5x - 2y = -1
- 5x -2*(-x - 1) = -1 (substitute for y from line 2.)
- 5x +2x +2 = -1 (Distribute multiplication over addition with the -2) [Check the signs on this]
- 7x + 2 = -1 (combine like terms)
- 7x = -3 (subtract 2 from both sides)
- x = -3/7 (divides both sides by 7)
This time we will use more than one equation at a time.
- x + y = -1
- 5x - 2y = -1
- We're trying to find a way to get rid of the y variable.
- 2x + 2y = -2 (multiply both sides of the first equation by 2)
- 5x - 2y = -1 (I'm going to add these two equations together)
- 2x +5x + 2y - 2y = -2 + -1 ( add the left sides and the right sides)
- 7x = -3 (combine like terms)
- x = -3/7 (divide both sides by 7)
Here is a quick way to solve it. Remember (-1) is equal to (-1). That's the reflexive property. Though I always liked to call it the "no duh" property.
But moving right along: X + Y = 5x - 2y ...we know this, now...
If we add 2y to each side: X + 3y = 5x .....good, now let's subtract X from each side...
Then we will get: 3y = 4x ....and if we solve for Y we get:
Y = (4/3)x ...Now we are ready to plug these in and solve.
X + Y = -1 now becomes: X + (4/3)X = -1
Let's combine like therms One plus four thirds is one and four thirds so..
(7/3)x = -1
We arrive at our answer by multiplying by the RECIPROCAL of the X coefficient:
X = -(3/7)


