HOw would I factor this out?
solve the polynomial inequalityx^3 + x^2 + 9x +9 <0
In addition to John's work:
(x2 + 9) is always positive, thus we have to find solution for x + 1 < 0 ---> x < -1
Interval (-∞, -1) is the solution for given inequality.
Begin by separating the factors into two groups:
(x3 + x2) + (9x + 9) < 0
Factor out the GCF in each parenthesis
x2(x + 1) + 9(x + 1) <0
Since factor in parenthesis is the same, we can combine the GCF's into their own factor
(x2 + 9)(x + 1) < 0