Need simplification for the maths problem
How to solve this maths problem (4a^-2 b)^2 (3a^3 b^-4)^-2
2 Answers
Since this is all multiplication and division, (no addition or subtraction),
you can simplify like variable parts.
You will need to use the fact that am = am-n ( for a not = 0)
an
AND, you need to know about negative exponents:
1 = an , a-n = bm
a-n b-m an
Or, think about any thing with a negative exponent can be moved to the other side of the fraction as that base to a positive exponent. (numerator to denominator, denominator to numerator)
Also, if you have (ambn)k = amkbnk (Or, you want to mulitply exponents here)
Now that we have some of the rules, there are a number of different ways
you could start to simplify this problem, but here is one way:
What if we apply the 2 and -2 exponents to what's inside the parantheses, respectively.
(4a-2b)2 is the same as 42a-4b2 (Remember, you can think of 4 as 41, and you can multiply exponents.
(3a3b-4)-2 is the same as what? (again, multiply the exponents)
After multiplying exponents, then you can eliminate any negative exponents by
putting those terms in the denominator with positive exponents.
Can you finish it from here?
(4a-2 b)2 (3a3 b-4)-2 = 42 a-4 b2 3-2 a-6 b8 = (16/9) a-10 b10 = (16/9)(b/a)10






Comments
AND, when you have the same base and are multiplying, you will add exponents:
For example, x3x4 = x7 (in general, aman= am+n)
You will need to use this rule when you combine with one of the variables in this problem
- George P. 2/25/2013Ok, did you find the answer yet?
(3a3b-4)-2 = 3-2a-6b8
So, you have (42a-4b2)(3-2a-6b8). Since, you have removed the outside exponents, this is just all multiplication, which we can re-order as:
42•3-2•a-4•a-6•b2•b8
423-2a-10b10
So, now let's get rid of negative exponents:
42b10 = 16b10
32a10 9a10
- George P. 2/25/2013Thank you very much for the response Mr George.highly recommend you as a teacher !!!
- Nish L. from New York, NY 2/26/2013