ther actual question is set up as
-3x + 5y=44
x + 5y = 32
ther actual question is set up as
-3x + 5y=44
x + 5y = 32
The way to solve this is to solve one of the equations for x or y.
The bottom one looks easier.
x=32-5y
Substitute that value into the top equation.
-3(32-5y)+5y=44
-96+15y+5y=44
20y=140
y=7
Now substitute y into the bottom equation
x+5(7)=32
x+35=32
x=-3
Now double check the answer by plugging in the answers to both equations.
-3(-3)+5(7)=44
-3+5(7)=32
The answer is x=-3 and y=7
Thank you very much for the help Ben.
Cindy V
- Cindy V. from Grand Rapids, MI 2/14/2013
-3x +5y =44x+5y=32
0 0
If you eliminate y first, then the process is lot simpler.
-3x + 5y=44 ......(1)
x + 5y = 32 ......(2)
(1)-(2): -4x = 12
x = -3, y = (32-x)/5 = (32+3)/5 = 7
- Robert J. 2/14/2013
Comments
Cindy,
This -3x +5y =44x+5y=32 is a bit ambiguous.
My guess is that it is actually two equations in two unknowns:
-3x +5y = 32 and 44x+5y=32
Can you clarify the problem?
BruceS
- BRUCE S. 2/14/2013BruceS, it is actually two seperate equations
-3x + 5y = 44
x+5y - 32
- Cindy V. from Grand Rapids, MI 2/14/2013